Difference between revisions of "Ring of sets"

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(Added book link to reference. Moved definition to a sub-page)
 
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Note that every [[Algebra of sets]] is also a ring, and that an [[Algebra of sets]] is sometimes called a '''Boolean algebra'''
 
Note that every [[Algebra of sets]] is also a ring, and that an [[Algebra of sets]] is sometimes called a '''Boolean algebra'''
==Definition==
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==[[/Definition|Definition]]==
A Ring of sets is a non-empty class {{M|R}}<ref>Page 19 - Halmos - Measure Theory - Springer - Graduate Texts in Mathematics (18)</ref> of sets such that:
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{{/Definition}}
* <math>\forall A\in R\forall B\in R(A\cup B\in R)</math>
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==A ring that exists==
* <math>\forall A\in R\forall B\in R(E-F\in R)</math>
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Take a set {{M|X}}, the [[Power set|power set]] of {{M|X}}, {{M|\mathcal{P}(X)}} is a ring (further still, an [[Algebra of sets|algebra]]) - the proof of this is trivial.
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This ring is important because it means we may talk of a "[[Ring generated by|ring generated by]]"
  
 
==First theorems==
 
==First theorems==
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{{End Proof}}
 
{{End Proof}}
 
{{End Theorem}}
 
{{End Theorem}}
 
 
{{Begin Theorem}}
 
{{Begin Theorem}}
 
Given any two rings, {{M|R_1}} and {{M|R_2}}, the intersection of the rings, {{M|R_1\cap R_2}} is a ring
 
Given any two rings, {{M|R_1}} and {{M|R_2}}, the intersection of the rings, {{M|R_1\cap R_2}} is a ring
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We know <math>\emptyset\in R</math>, this means we know at least <math>\{\emptyset\}\subseteq R_1\cap R_2</math> - it is non empty.
 
We know <math>\emptyset\in R</math>, this means we know at least <math>\{\emptyset\}\subseteq R_1\cap R_2</math> - it is non empty.
  
Take any <math>A,B\in R_1\cap R_2</math>
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Take any <math>A,B\in R_1\cap R_2</math> (which may be the empty set, as shown above)
  
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Then:
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* <math>A,B\in R_1</math>
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* <math>A,B\in R_2</math>
  
{{End Proof}}
 
{{End Theorem}}
 
  
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This means:
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* <math>A\cup B\in R_1</math> as {{M|R_1}} is a ring
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* <math>A-B\in R_1</math> as {{M|R_1}} is a ring
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* <math>A\cup B\in R_2</math> as {{M|R_2}} is a ring
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* <math>A-B\in R_2</math> as {{M|R_2}} is a ring
  
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But then:
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* As <math>A\cup B\in R_1</math> and <math>A\cup B\in R_2</math> we have <math>A\cup B\in R_1\cap R_2</math>
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* As <math>A- B\in R_1</math> and <math>A- B\in R_2</math> we have <math>A- B\in R_1\cap R_2</math>
  
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Thus <math>R_1\cap R_2</math> is a ring.
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{{End Proof}}
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{{End Theorem}}
 
==References==
 
==References==
 
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<references/>
 
{{Definition|Measure Theory}}
 
{{Definition|Measure Theory}}

Latest revision as of 17:21, 18 August 2016

A Ring of sets is also known as a Boolean ring

Note that every Algebra of sets is also a ring, and that an Algebra of sets is sometimes called a Boolean algebra

Definition

A Ring of sets is a non-empty class R[1] of sets such that:

  • ARBR[ABR]
  • ARBR[ABR]

A ring that exists

Take a set X, the power set of X, P(X) is a ring (further still, an algebra) - the proof of this is trivial.

This ring is important because it means we may talk of a "ring generated by"

First theorems

[Expand]

The empty set belongs to every ring

[Expand]

Given any two rings, R1 and R2, the intersection of the rings, R1R2 is a ring

References

  1. Jump up Page 19 -Measure Theory - Paul R. Halmos