Quotient topology
\require{AMScd} \begin{equation}\begin{CD} S^{{\mathcal{W}}_\Lambda}\otimes T @>j>> T\\ @VVV @VV{\End P}V\\ (S\otimes T)/I @= (Z\otimes T)/J \end{CD}\end{equation}
Quotient map
Let (X,\mathcal{J}) and (Y,\mathcal{K}) be topological spaces and let p:X\rightarrow Y be a surjective map.
p is a quotient map[1] if we have U\in\mathcal{K}\iff p^{-1}(U)\in\mathcal{J}
Notes
Stronger than continuity
If we had \mathcal{K}=\{\emptyset,Y\} then p is automatically continuous (as it is surjective), the point is that \mathcal{K} is the largest topology we can define on Y such that p is continuous
See Motivation for quotient topology for a discussion on where this goes.
Definition
If (X,\mathcal{J}) is a topological space, A is a set, and p:(X,\mathcal{J})\rightarrow A is a surjective map then there exists exactly one topology \mathcal{J}_Q relative to which p is a quotient map. This is the quotient topology induced by p
TODO: Munkres page 138
References
- Jump up ↑ Topology - Second Edition - James R Munkres