Dense
DENSE IS SPRAWLED OVER LIKE 4 PAGES
- I've distilled some of it Equivalent statements to a set being dense there, but I need to .... fix this page up, it's a mess. I should probably move the equivalent definitions to here, as they're like... "easy equivalent" and may well be definitions, not like ... a proposition of equivalence.
- That's a woolly distinction
Anyway, there is work required to fix this up.
SEE: List of topological properties for a smaller and neater listContents
[hide]Temporary summary
Let (X,J) be a topological space, and (X,d) be a metric space. Then for an arbitrary subset of X, say A∈P(X), we say A is dense in X if:
- Topological: ∀U∈J[U∩A≠∅][1]
- There are some equivalent conditions[Note 1]
- Closure(A)=X (sometimes written: ¯A=X)
- X−A contains no (non-empty) open subsets of X
- Symbolically: ∀U∈J[U⊈ - which is easily seen to be equivalent to: \forall U\in\mathcal{J}\exists p\in U[p\notin X-A]
- X-A has no interior points[Note 2]
- Symbolically we may write this as: \forall p\in X-A\left[\neg\left(\exists U\in\mathcal{J}[p\in U\wedge U\subseteq A\right)\right]
- \iff\forall p\in X-A\forall U\in\mathcal{J}[\neg(p\in U\wedge U\subseteq A)]
- \iff\forall p\in X-A\forall U\in\mathcal{J}[(\neg(p\in U))\vee(\neg(U\subseteq A))] - by the negation of logical and
- \iff\forall p\in X-A\forall U\in\mathcal{J}[p\notin U\vee U\nsubseteq A] - of course by the implies-subset relation we see (A\subseteq B)\iff(\forall a\in A[a\in B]), thus:
- \iff\forall p\in X-A\forall U\in\mathcal{J}\big[p\notin U\vee(\exists q\in U[q\notin A])\big]
- Symbolically we may write this as: \forall p\in X-A\left[\neg\left(\exists U\in\mathcal{J}[p\in U\wedge U\subseteq A\right)\right]
- There are some equivalent conditions[Note 1]
- Metric: \forall x\in X\forall\epsilon>0[B_\epsilon(x)\cap A\neq\emptyset
- There are no equivalent statements at this time.
The rest of the page continues below. It will be refactored soon.
Definition
Let (X,\mathcal{ J }) be a topological space and let A\in\mathcal{P}(X) be an arbitrary subset of X. We say "A is dense in X if[2]:
- \overline{A}=X - that is to say that the closure of A is the entirety of X itself.
Some authors give the following equivalent definition to A being dense[1]:
- \forall U\in\mathcal{J}\exists a\in A[U\ne\emptyset\implies y\in U], which is obviously equivalent to: \forall U\in\mathcal{J}[U\ne\emptyset \implies A\cap U\ne\emptyset] (see Claim 1 below)
- In words:
Metric spaces definition
Let (X,d) me a metric space, we say that E\in\mathcal{P}(X) (so E is an arbitrary subset of X) if[1]:
- \forall x\in X\forall\epsilon>0[B_\epsilon(x)\cap E\ne\emptyset] - where B_r(x) denotes the open ball of radius r, centred at x
Claim 2: for a metric space (X,d) a subset, E\in\mathcal{P}(X) is dense in the metric sense if and only if it is dense in (X,\mathcal{ J }) where J is the topology induced by the metric d.
Proof of claims
Claim 1
This is used for both cases, and it should really be factored out into its own page. Eg:
The message provided is:
This proof has been marked as an page requiring an easy proof
Claim 2
The message provided is:
This proof has been marked as an page requiring an easy proof
See also
Notes
- Jump up ↑ These are not just logically equivalent to density, they could be definitions for density, and may well be in some books.
- Jump up ↑ a\in A is an interior point of A if:
- \exists U\in\mathcal{J}[a\in U\wedge U\subseteq A] (by Functional Analysis - V1 - Dzung M. Ha - can't use references in reference tag!)
- Jump up ↑ This is a trivial restatement of the claim and not worth going on its own page, unless it can be generalised (eg detached from dense-ness)