Doctrine:Differentiation notation & terminology
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Almost everyone has a different view of how to write derivatives. I have compiled these as "the best of the best" and tweaked it a little to enhance readability and consistency of the notation.
Notation & terminology
Derivative
- df|a - the derivative of f at a. A linear map from the domain of f to the co-domain of f
- This means f is differentiable at a and df|a is its derivative; not differential, that is something else.
We use the d and the | as brackets. Everything between is what we're taking the derivative of.
- Example: The chain rule - d(g∘f)|a=dg|f(a)∘df|a[Note 1]
The notation employed by Munkres and Spivak in Df(a) makes it hard to tell if it is referring to the derivative of f(a) considered as a function (which may be constant, or f might map a to a function that can be differentiated itself!) and if so where. This is especially true when looking at functions of functions.
TODO: This paragraph is repetitive, fix it
It is common to want to consider df|, which takes points in the domain of f to their derivatives at that point. This is a slight abuse of notation however in our notation it is not a big leap to see df| as a function that takes the domain of f to a function (from the domain of f to the co-domain of f). Then:
- df|(a) simply reads like another way of saying df|a.
Overview
Let (X,∥⋅∥X) and (Y,∥⋅∥Y) be normed spaces and let f:X→Y be a function. Then:
- f is differentiable at a∈X if:
- There exists a neighbourhood of a, N and
- There exists a linear map, λ:X→Y[Note 2]
such that:
- limh→0(∥f(a+h)−f(a)−λ(h)∥Y∥h∥X)=0- Caution:There are other expressions for this limit that may be equivalent. This has not been decided/confirmed yet
Alternate expressions:
Caveats/Pending questions
- Is this limit equivalent to the definition of differentiable that is least constraining?
- Are there normed subspaces? If so must it contain 0 (so h may tend to it?) - additionally if the neighbourhood of a is open in X and X is simply a topological subspace the requirements become blurred.
- A normed subspace is almost certainly a vector subspace in its own right, so this shouldn't be a problem. However I mention this to remind myself, and as food for thought.
Notes
- Jump up ↑ We don't need the brackets around g∘f however we can agree that this is easier to read than:
- dg∘f|a=dg|f(a)∘df|a
- Jump up ↑ Recall that X and Y are vector spaces