Difference between revisions of "Equivalent conditions to a set being bounded"
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Latest revision as of 23:12, 18 March 2017
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Contents
[hide]Statement
Let (X,d) be a metric space and let A∈P(X) be an arbitrary subset of X. Then the following are all logical equivalent to each other[Note 1]:
Proof of claims
[Expand]
1⟹2) (∃C<∞ ∀a,b∈A[d(a,b)<C])⟹(∀x∈X∃C<∞∀a∈A[d(a,x)<C]), that boundedness implies condition 2
[Expand]
2⟹1) (∀x∈X∃C<∞∀a∈A[d(a,x)<C])⟹(∃C<∞ ∀a,b∈A[d(a,b)<C]), that condition 2 implies boundedness
Notes
- Jump up ↑ Just in case the reader isn't sure what this means, if A and B are logically equivalent then:
- A⟺B. In words "A if and only if B"
References
Categories:
- Stub pages
- Pages requiring work
- Pages requiring proofs: Easy proofs
- Pages requiring proofs
- Theorems
- Theorems, lemmas and corollaries
- Analysis Theorems
- Analysis Theorems, lemmas and corollaries
- Analysis
- Functional Analysis Theorems
- Functional Analysis Theorems, lemmas and corollaries
- Functional Analysis
- Topology Theorems
- Topology Theorems, lemmas and corollaries
- Topology
- Metric Space Theorems
- Metric Space Theorems, lemmas and corollaries
- Metric Space