Difference between revisions of "Inductive set"

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(Created page with "{{Stub page|grade=A*|msg=Needs another reference}} __TOC__ ==Definition== Let {{M|I}} be a set. We call {{M|I}} an ''inductive set'' if{{rITSTHJ}} both of the following pr...")
 
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#* {{M|S(x)}} denotes the [[successor set]] of {{M|X}}
 
#* {{M|S(x)}} denotes the [[successor set]] of {{M|X}}
 
{{Caveat|Note that this certainly describes the natural numbers as we require {{M|\emptyset\in I}}, so they're in there. The problem is that rule 2 seems to require that for every element {{M|n}} that {{M|n\cup\{n\} }} is in there too.}} - this seems to be intended{{rSTTJ}}
 
{{Caveat|Note that this certainly describes the natural numbers as we require {{M|\emptyset\in I}}, so they're in there. The problem is that rule 2 seems to require that for every element {{M|n}} that {{M|n\cup\{n\} }} is in there too.}} - this seems to be intended{{rSTTJ}}
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==See also==
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* [[The natural numbers]]
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* [[The axiom of infinity]] - positing that an inductive set exists.
 
==References==
 
==References==
 
<references/>
 
<references/>
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{{Definition|Set Theory}}

Latest revision as of 15:56, 3 February 2017

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Definition

Let I be a set. We call I an inductive set if[1] both of the following properties hold:

  1. I - often written 0I as 0 is represented by the - and
  2. n[nIS(n)I] - often written as "if nI then (n+1)I"

Caveat:Note that this certainly describes the natural numbers as we require I, so they're in there. The problem is that rule 2 seems to require that for every element n that n{n} is in there too. - this seems to be intended[2]

See also

References

  1. Jump up Introduction To Set Theory - Third Edition, Revised and Expanded - Karel Hrbacek & Thomas Jech
  2. Jump up Set Theory - Thomas Jech - Third millennium edition, revised and expanded