Difference between revisions of "The zero-to-the-power-of-zero problem"
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| + | {{Stub page|grade=A|msg=Oh wow I really didn't add much to this page! It needs work! At least: | ||
| + | * Limit argument | ||
| + | * [[Geometric distribution]] when {{M|p\eq 1}} - calculating the [[Expectation]] in this case involves {{M|0^0\eq 1}} | ||
| + | [[User:Alec|Alec]] ([[User talk:Alec|talk]]) 21:09, 30 November 2017 (UTC)}} | ||
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|title=The {{M|0^0}} problem | |title=The {{M|0^0}} problem | ||
Latest revision as of 21:09, 30 November 2017
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- Limit argument
- Geometric distribution when [ilmath]p\eq 1[/ilmath] - calculating the Expectation in this case involves [ilmath]0^0\eq 1[/ilmath]
| The [ilmath]0^0[/ilmath] problem | |
| [ilmath]0^0[/ilmath] |
Contents
Problem
- For a detailed list of where the problem matters or occurs on this site see Category for such problemsEditors:[Note 1]
Tentative solutions
Current thinking
Approach 1: [ilmath]x^y\eq e^{y\text{ln}(x)} [/ilmath]
Using the extended real values ([ilmath]\mathbb{R}\cup\{-\infty,+\infty\} [/ilmath])[Note 2]
Notes
- ↑ editors see/use Template:0^0 problem
- ↑ Where we conventionally think of [ilmath]+\infty[/ilmath] as some sort of
