Difference between revisions of "Exercises:Mond - Topology - 1/Question 7"

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(Created page with "<noinclude> ==Section B== ===Question 7=== </noinclude>Let {{M|D^2}} denote the closed unit disk in {{M|\mathbb{R}^2}} and define an equivalence relation on {{M|D^2}}...")
 
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* '''Hint: ''' first define a [[surjection]] {{M|(:D^2\rightarrow\mathbb{S}^2)}} mapping all of {{M|\partial D^2}} to the north pole. This may be defined using a good picture or a formula.
 
* '''Hint: ''' first define a [[surjection]] {{M|(:D^2\rightarrow\mathbb{S}^2)}} mapping all of {{M|\partial D^2}} to the north pole. This may be defined using a good picture or a formula.
 
====Solution====
 
====Solution====
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{{float-right|{{Exercises:Mond - Topology - 1/Pictures/Q7 - 1}}}}
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==Notes==
 
==Notes==

Revision as of 11:42, 8 October 2016

Section B

Question 7

Let [ilmath]D^2[/ilmath] denote the closed unit disk in [ilmath]\mathbb{R}^2[/ilmath] and define an equivalence relation on [ilmath]D^2[/ilmath] by setting [ilmath]x_1\sim x_2[/ilmath] if [ilmath]\Vert x_1\Vert=\Vert x_2\Vert[/ilmath]. Show that [ilmath]\frac{D^2}{\sim} [/ilmath] is homeomorphic to [ilmath]\mathbb{S}^2[/ilmath] - the sphere.

  • Hint: first define a surjection [ilmath](:D^2\rightarrow\mathbb{S}^2)[/ilmath] mapping all of [ilmath]\partial D^2[/ilmath] to the north pole. This may be defined using a good picture or a formula.

Solution

The idea is to double the radius of [ilmath]D^2[/ilmath], then pop it out into a hemisphere, then pull the rim to a point
Picture showing the "expanding [ilmath]D^2[/ilmath]", the embedding-in-[ilmath]\mathbb{R}^3[/ilmath] part, and the "popping out"

Notes

References