Difference between revisions of "Dense"

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(Added references, added metric space definition)
m (Added equivalence claim for metric space definition to their induced topological spaces.)
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** In words: Every [[open ball]] at every point overlaps with {{M|E}}. (i.e: every open ball at every point contains at least 1 point in common with {{M|E}})
 
** In words: Every [[open ball]] at every point overlaps with {{M|E}}. (i.e: every open ball at every point contains at least 1 point in common with {{M|E}})
 
** This is equivalent to {{M|1=\forall x\in X\forall\epsilon>0\exists y\in E[y\in B_\epsilon(x)]}}<sup>Found in:</sup>{{rW2014LNFARS}} (see '''''Claim 1''''')<ref group="Note">This is a trivial restatement of the claim and not worth going on its own page, unless it can be generalised (eg detached from dense-ness)</ref>
 
** This is equivalent to {{M|1=\forall x\in X\forall\epsilon>0\exists y\in E[y\in B_\epsilon(x)]}}<sup>Found in:</sup>{{rW2014LNFARS}} (see '''''Claim 1''''')<ref group="Note">This is a trivial restatement of the claim and not worth going on its own page, unless it can be generalised (eg detached from dense-ness)</ref>
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'''''Claim 2: ''''' for a [[metric space]] {{M|(X,d)}} a subset, {{M|E\in\mathcal{P}(X)}} is dense in the metric sense {{iff}} it is dense in {{Top.|X|J}} where {{M|J}} is the [[topology induced by the metric]] {{M|d}}.
 
==Proof of claims==
 
==Proof of claims==
 
===Claim 1===
 
===Claim 1===
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* [[The intersection of two sets is non-empty if and only if there exists a point in one set that is in the other set]]
 
* [[The intersection of two sets is non-empty if and only if there exists a point in one set that is in the other set]]
 
{{Requires proof|easy=true|grade=C|msg=It is obvious that {{M|1=(B_\epsilon(x)\cap E\ne\emptyset)\iff(\exists y\in E[y\in B_\epsilon(x)])}}}}
 
{{Requires proof|easy=true|grade=C|msg=It is obvious that {{M|1=(B_\epsilon(x)\cap E\ne\emptyset)\iff(\exists y\in E[y\in B_\epsilon(x)])}}}}
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===Claim 2===
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{{Requires proof|easy=true|grade=C|msg=Easy for someone informed of what a metric space and topology is. The claim means showing that if {{Top.|X|J}} is the [[topological space induced by a metric space]] for a [[metric space]] {{M|(X,d)}} then {{M|E}} is dense in {{Top.|X|J}} {{iff}} {{M|E}} is dense in {{M|(X,d)}}}}
 
==See also==
 
==See also==
 
* [[Equivalent statements to a set being dense]]
 
* [[Equivalent statements to a set being dense]]

Revision as of 19:40, 28 October 2016

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Revise page, add some links to propositions or theorems using the dense property. Also more references, then demote

Definition

Let [ilmath](X,\mathcal{ J })[/ilmath] be a topological space and let [ilmath]A\in\mathcal{P}(X)[/ilmath] be an arbitrary subset of [ilmath]X[/ilmath]. We say "[ilmath]A[/ilmath] is dense in [ilmath]X[/ilmath] if[1]:

  • [ilmath]\overline{A}=X[/ilmath] - that is to say that the closure of [ilmath]A[/ilmath] is the entirety of [ilmath]X[/ilmath] itself.

Some authors give the following equivalent definition to [ilmath]A[/ilmath] being dense[2]:

Metric spaces definition

Let [ilmath](X,d)[/ilmath] me a metric space, we say that [ilmath]E\in\mathcal{P}(X)[/ilmath] (so [ilmath]E[/ilmath] is an arbitrary subset of [ilmath]X[/ilmath]) if[2]:

  • [ilmath]\forall x\in X\forall\epsilon>0[B_\epsilon(x)\cap E\ne\emptyset][/ilmath] - where [ilmath]B_r(x)[/ilmath] denotes the open ball of radius [ilmath]r[/ilmath], centred at [ilmath]x[/ilmath]
    • In words: Every open ball at every point overlaps with [ilmath]E[/ilmath]. (i.e: every open ball at every point contains at least 1 point in common with [ilmath]E[/ilmath])
    • This is equivalent to [ilmath]\forall x\in X\forall\epsilon>0\exists y\in E[y\in B_\epsilon(x)][/ilmath]Found in:[3] (see Claim 1)[Note 1]

Claim 2: for a metric space [ilmath](X,d)[/ilmath] a subset, [ilmath]E\in\mathcal{P}(X)[/ilmath] is dense in the metric sense if and only if it is dense in [ilmath](X,\mathcal{ J })[/ilmath] where [ilmath]J[/ilmath] is the topology induced by the metric [ilmath]d[/ilmath].

Proof of claims

Claim 1

This is used for both cases, and it should really be factored out into its own page. Eg:

Grade: C
This page requires one or more proofs to be filled in, it is on a to-do list for being expanded with them.
Please note that this does not mean the content is unreliable. Unless there are any caveats mentioned below the statement comes from a reliable source. As always, Warnings and limitations will be clearly shown and possibly highlighted if very important (see template:Caution et al).
The message provided is:
It is obvious that [ilmath](B_\epsilon(x)\cap E\ne\emptyset)\iff(\exists y\in E[y\in B_\epsilon(x)])[/ilmath]

This proof has been marked as an page requiring an easy proof

Claim 2

Grade: C
This page requires one or more proofs to be filled in, it is on a to-do list for being expanded with them.
Please note that this does not mean the content is unreliable. Unless there are any caveats mentioned below the statement comes from a reliable source. As always, Warnings and limitations will be clearly shown and possibly highlighted if very important (see template:Caution et al).
The message provided is:
Easy for someone informed of what a metric space and topology is. The claim means showing that if [ilmath](X,\mathcal{ J })[/ilmath] is the topological space induced by a metric space for a metric space [ilmath](X,d)[/ilmath] then [ilmath]E[/ilmath] is dense in [ilmath](X,\mathcal{ J })[/ilmath] if and only if [ilmath]E[/ilmath] is dense in [ilmath](X,d)[/ilmath]

This proof has been marked as an page requiring an easy proof

See also

Notes

  1. This is a trivial restatement of the claim and not worth going on its own page, unless it can be generalised (eg detached from dense-ness)

References

  1. Introduction to Topological Manifolds - John M. Lee
  2. 2.0 2.1 Functional Analysis - Volume 1: A gentle introduction - Dzung Minh Ha
  3. Warwick 2014 Lecture Notes - Functional Analysis - Richard Sharp