Tensor product of tensors
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Contents
[hide]Definition
Let f and g be "tensors of rank k and ℓ respectively", then we can define the tensor product, a rank k+ℓ tensor, as follows[1]:
- (f⊗g)(u1,…,uk,v1,…,vℓ):=f(u1,…,uk)⋅g(v1,…,vℓ)
To call f⊗g a tensor we require:
- f⊗g to be multilinear map
This is easily seen
Properties
Let f, g and h be "compatible" tensors. Then:
- Associativity: f⊗(g⊗h)=(f⊗g)⊗h
- Homogeneity: (cf)⊗g=c(f⊗g)=f⊗(cg) - for scalar c∈F
- Distributivity: (suppose that f and g are of the same rank/order (among other things?)) then:
- (f+g)⊗h=f⊗h+g⊗h
- h⊗(f+g)=h⊗f+h⊗g
- Suppose that we are dealing with Lk(V) in Munkres' notation, or L(V,…,V⏟k lots of V;F) in mine for vec space (V,F) of dimension n, then:
- If e1,…,en is a basis of V we have:
- The corresponding "elementary tensors", ϕI satisfy the equation:
- ϕI=ϕi1⊗ϕi2⊗⋯⊗ϕik−1⊗ϕikwhere I=(i1,…,ik) and each ij∈{1,…,n}
- ϕI=ϕi1⊗ϕi2⊗⋯⊗ϕik−1⊗ϕik
- The corresponding "elementary tensors", ϕI satisfy the equation:
- If e1,…,en is a basis of V we have:
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Easy to do, I've done most of this on paper already.
- Property 4 is easier and more significant than I first thought. It just shows ⊗ is a nice way to write a product, a nice way to write ϕI.
Notes
- ϕi(ej):={1if i=j0otherwise - these align with dual basis vectors
- ϕI(ej1,…,ejk):={1if J=I0otherwise
- ϕI(ej1,…,ejk)=ϕi1(ej1)⋅ … ⋅ϕik(ejk) follows easily.
- where I and J are both k-tuples of elements of {1,…,n}
- ϕI(ej1,…,ejk)=ϕi1(ej1)⋅ … ⋅ϕik(ejk) follows easily.
These are the elementary tensors. Tensors of the form ϕI form a basis of L(V,…,V⏟k lots of V;F)
This is easy to see, see page 222 of Munkres on manifolds for details.