Distributivity of intersections across unions

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Created for use with the ring of sets generated by a semi-ring is the set containing the semi-ring and all finite disjoint unions, the theorem is easy and routine, at least in the finite cases

Statement

  1. A(BC)=(AB)(AC)
  2. A(ni=1Bi)=ni=1(ABi) - Easy to do, use induction

Proof

Grade: C
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First one is routine chapter-1 for first-years, second one is easy using induction

This proof has been marked as an page requiring an easy proof

See also

References