Distributivity of intersections across unions
From Maths
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Created for use with the ring of sets generated by a semi-ring is the set containing the semi-ring and all finite disjoint unions, the theorem is easy and routine, at least in the finite cases
Contents
[hide]Statement
- A∩(B∪C)=(A∩B)∪(A∩C)
- A∩(⋃ni=1Bi)=⋃ni=1(A∩Bi) - Easy to do, use induction
Proof
Grade: C
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This proof has been marked as an page requiring an easy proof
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First one is routine chapter-1 for first-years, second one is easy using induction
This proof has been marked as an page requiring an easy proof
See also
- Distributivity of unions across intersections (almost the same: A∪(B∩C)=(A∪B)∩(A∪C))
References