Quotient vector space
From Maths
- Note: see Quotient for other types of quotient
Grade: C
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Contents
[hide]Definition
Given:
- A vector space (V,F) over a field F and
- A vector subspace W⊆V
We define an:
- Equivalence relation on V defined as:
- v∼v′ if v−v′∈W
Here [v] denotes the equivalence class of v under ∼, that is:
- [v]:={u∈V|v∼u}
Then the following two diagrams commute
Diagram for addition on equivalence classes
|
Note that here:
|
Diagram | Key |
---|---|
+:V∼×V∼→V∼ is given by π∘+∘(π×π)−1. This means that [u]+[v]=π(π−1([u])+π−1([v]))=[x∈π−1([u])+y∈π−1([v])]⏟Well-defined-ness=[u+v][Note 1] |
Note that:
- The dashed arrow labeled + denotes the induced binary operation on V∼, in the context of factoring functions we often write the function induced by f as ˜f however (as usual) the meaning of addition is given by the context, so it is not ambiguous to define addition of V∼ where addition on V is already defined.
- The 'well-defined-ness' need not be checked as it is used in the proof of factorising functions - it is mentioned here only to explain the abuse of notation
Diagram for scalar multiplication
|
Note that here:
|
Diagram | Key |
---|---|
∗:F×V∼→V∼ is given by π∘∗∘(i×π)−1. That is α[v]=π(απ−1([v]))=[αx for x∈π−1([v])]⏟well-defined-ness=[αv][Note 2] |
Overview of proofs
Usually we simply say:
- Addition defined by:
- [v]+[u]=[v+u] and check it is well defined (this is to check that whichever representatives we choose of a∈[u] and b∈[v] that [a+b]=[u+v] still
- Scalar multiplication defined by:
- α[v]=[αv] and again, check this is well defined (that is for whichever a∈[v] we choose to represent [v] that [αa]=[αv]
This isn't wrong. However by using diagrams we can get a much "purer" proof which only involves checking the conditions of factoring functions - this shifts the notion of "well defined" to this operation and we simply apply a theorem.
Proof of claims
[Expand]
Claim 1: v∼v′ is indeed an equivalence relation
[Expand]
Claim 2: The diagram for addition commutes
[Expand]
Claim 1: The diagram for multiplication commutes
To-do notes
- This method is "purer" and more advanced then is seen when this concept is first introduced. A "simple" version ought to be created
- A summary section of factorising functions ought to be transcluded into this page.
- Some examples
TODO: These things
Notes
- Jump up ↑ This is where well-defined-ness comes into play, but the Factor (function) theorem already takes this into account. We abuse the notation when writing π−1 as this is of course a subset, it's okay though because whichever member of the subset we take, the equivalence class of the addition with another representative of the second term is the same
- Jump up ↑ Note that π−1([v]) is actually a set but as Factor (function) shows it doesn't matter what representative we take. This is an abuse of notation.