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Revision as of 21:18, 22 November 2015

Note: see Limit page for other kinds of limits

Definition

Given a sequence (xn)n=1X, a metric space (X,d) (that is complete) and a point xX, the sequence (xn) is said to[1][Note 1]:

  • have limit x or converge to x

When:

  • ϵ>0NNnN[n>Nd(x,xn)<ϵ][Note 2]
    (note that ϵR, obviously - as the co-domain of d is R)
  • Read this as:
    for all ϵ greater than zero, there exists an N in the natural numbers such that for all n that are also natural we have that:
    whenever n is beyond N that xn is within ϵ of x

Equivalent definitions

Note: where it is not obvious changes have a { underneath them
[Expand]

lim

Discussion

Requiring x\in X

If x\notin X then d(x_n,x) is undefined, as d:X\times X\rightarrow\mathbb{R}_{\ge_0} , that is the distance metric is only defined for things in X

Process

The idea is that defining "tends towards x" is rather difficult, to sidestep this we just say "we can get as close as we like to" instead. This is the purpose of \epsilon.

We say that "if you give me an \epsilon>0 - as small as you like - I can find you a point of the sequence (N) where all points after are within \epsilon of x (where d(\cdot,\cdot) is our notion of distance)

  • That is after N in the sequence, so that's x_{n+1},x_{n+1},\ldots the distance between x_{N+i} and x is <\epsilon
    This is exactly what n>N\implies d(x_n,x)<\epsilon says, it says that:
    • whenever n>N we must have d(x_n,x)<\epsilon

As per the nature of implies we may have d(x_n,x)<\epsilon without n>N, it is only important that WHENEVER we are beyond N in the sequence that d(x_n,x)<\epsilon

Example
Sequencelimit.gif Here:
  • x-axis scale is from 0 to 12.6, marks are shown every unit.
  • y-axis scale starts from 0 and is marked every 0.25 units.
  • The sequence is any sequence of points on the wavy function shown.
    • The limit of this is clearly 1
  • The two horizontal lines show 1-\epsilon and 1+\epsilon
  • The vertical line shows one possible value where every point after it is within \epsilon of 1
  • due to technical limitations the function f(x)=1+\frac{\sin(\pi x)}{\frac{1}{4}x^2} is shown
  • The curves are bounds on the function.

Notice that at x=1 that , in fact the curve is within \pm\epsilon several times before we reach the vertical line, this is the significance of the implies sign, when we write A\implies B we require that whenever A is true, B must be true, but B may be true regardless of what A is.

Note that after the vertical line the function is always within the bounds.

Because of this any N'>N may be used too, as if n>N' and N'>N then n>N'>N so n>N - this proves that if N works then any larger N' will too. There is no requirement to find the smallest N that'll work, just an N such that n>N\implies d(x_n,x)<\epsilon

See also

Notes

  1. Jump up Actually Maurin gives:
    • \forall\epsilon>0\exists N\in\mathbb{N}\forall n[n\ge N\implies d(x_n,x)<\epsilon] (the change is the \ge sign between the n and N) but as we shall see this doesn't matter
  2. Jump up In Krzysztof Maurin's notation this can be written as:
    • \bigwedge_{\epsilon>0}\bigvee_{N\in\mathbb{N} }\bigwedge_{n>N}d(x_n,x)<\epsilon

References

  1. Jump up Krzysztof Maurin - Analysis - Part 1: Elements