Topological retraction
From Maths
Grade: A*
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[hide]Proof
Note that if r∘iA=IdA then r∗∘(iA)∗=(IdA)∗
- So r∗∘(iA)∗ must be a bijection
- By if the composition of two functions is a bijection then the initial map is injective and the latter map is surjective
- We see:
- r∗:π1(X,a)→π1(A,a) is surjective
- (iA)∗:π1(A,a)→π1(X,a) is injective
- We see:
- By if the composition of two functions is a bijection then the initial map is injective and the latter map is surjective
Alec's thought: can we use the first group isomorphism theorem on r∗ to get π1(A,a) from π1(X,a) or something?
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Demote to grade A once tidied up. Find other sources. Be sure to link to deformation retraction and strong deformation retraction
Definition
Let (X,J) be a topological space and let A∈P(X) be considered a s subspace of X. A continuous map, r:X→A is called a retraction if[1]:
- The restriction of r to A (the map r|A:A→A given by r|A:a↦r(a)) is the identity map, IdA:A→A given by IdA:a↦a
If there is such a retraction, we say that: A is a retract[1] of X.
Claim 1:
- This is equivalent to the condition: r∘iA=IdA where iA denotes the inclusion map, iA:A↪X given by iA:a↦x
TODO: In the case of A=∅ - does it matter? I don't think so, but check there is nothing noteworthy about it. Also proof of claims
See also
- Types of topological retractions - comparing retraction with deformation retraction and strong deformation retraction
Important theorems
- For a retraction the induced homomorphism on the fundamental group is surjective
- ∀p∈A the induced homomorphism on fundamental groups of the retraction, r∗:π1(X,p)→π1(A,p) is surjective
- For the inclusion map of a retract of a space the induced homomorphism on the fundamental group is injective
- ∀p∈A the induced homomorphism on fundamental groups of the inclusion map, iA:A↪X, which is (iA)∗:π1(A,p)→π1(X,p) is injective
Lesser theorems
- A retract of a connected space is connected
- A retract of a compact space is compact
- A retract of a retract of X is a retract of X
- A retract of a simply connected space is simply connected